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Question
What is the equivalent resistance across points A and B in the circuit given below?
Options
8Ω
12Ω
16Ω
32Ω
MCQ
Solution
8Ω
Explanation:
Given, resistances 10Ω and 2.5Ω are in parallel,
`R_1 = (10 xx 2.5)/(10 + 25) = 2Omega`
Now, 2Ω and 10Ω are in series, R2 = 10 + 2 = 12Ω
R2 and 12Ω are in parallel, `1/R_3 = 1/12 + 1/12`
⇒ R3 = 6Ω
Now, R3 and 10Ω are in series, R4 = 6 + 10 = 16Ω
Now, R4 and 16Ω are in parallel.
`1/R = 1/16 + 1/16 ⇒ R = 16/2 = 8Omega`
∴ Net equivalent resistance across points A and B is 8Ω.
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