मराठी

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106 m). - Science

Advertisements
Advertisements

प्रश्न

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106 m).

संख्यात्मक

उत्तर

Mass of the earth (M) = 6 × 1024 kg 

Radius of the Earth (R) = 6.4 × 106 m

Mass of the object (m) = 1kg

Universal constant (G) = `6.67 × 10^-11 (Nm)^2/(kg)^2`

We know that, F = `(GM_eM_(body))/r_e^2`

F = `(6.67×10^-11 × 6×10^24 × 1)/(6.4×10^6)^2`

This gives, F = 9.8 N

Hence the gravitational force between the object and the earth = 9.8 N.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Gravitation - Exercises [पृष्ठ १४३]

APPEARS IN

एनसीईआरटी Science [English] Class 9
पाठ 10 Gravitation
Exercises | Q 3 | पृष्ठ १४३

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Write the answer of the question with reference to laws of gravitation.

State the universal law of gravitation.


At noon, the sun and the earth pull the objects on the earth's surface in opposite directions. At midnight, the sun and the earth pull these objects in same direction. Is the weight of an object, as measured by a spring balance on the earth's surface, more at midnight as compared to its weight at noon?


Suppose the gravitational potential due to a small system is k/r2 at a distance r from it. What will be the gravitational field? Can you think of any such system? What happens if there were negative masses?


A person brings a mass of 1 kg from infinity to a point A. Initially the mass was at rest but it moves at a speed of 2 m s −1 as it reaches A. The work done by the person on the mass is −3 J. The potential at A is


What is the difference between gravity and gravitation?


Solve the following problem.

Find the gravitational force between the Sun and the Earth.
Given Mass of the Sun = 1.99 × 1030 kg
Mass of the Earth = 5.98 × 1024 kg
The average distance between the Earth and the Sun = 1.5 × 1011 m.


For the weight of body of mass 5 kg to be zero on equator of the earth, angular velocity of the earth must be (The radius of earth = 6400 km, acceleration due to gravity = 10 m/s2).


If the law of gravitation, instead of being inverse-square law, becomes an inverse-cube law- ______.

  1. planets will not have elliptic orbits.
  2. circular orbits of planets is not possible.
  3. projectile motion of a stone thrown by hand on the surface of the earth will be approximately parabolic.
  4. there will be no gravitational force inside a spherical shell of uniform density.

Give scientific reasons for the following:

Newton's gravitational law is the universal law of gravitation.


Two particles of equal mass 'm' go around a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle with respect to its centre of mass is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×