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प्रश्न
What mass of copper hydroxide is precipitated by using 200 gm of sodium hydroxide?
\[\ce{2NaOH + CuSO4 -> Na2SO4 + Cu(OH)2↓}\]
[Cu = 64, Na = 23, S = 32, H = 1]
उत्तर
\[\ce{2NaOH + CuSO4 -> Na2SO4 + Cu(OH)2 ↓}\]
Molecular mass of Cu(OH)2 = 64 + 16(2) + 1(2) = 98
Molecular mass of NaOH = 2(23 + 16 + 1) = 80
∴ 80 g sodium hydroxide forms = 98 g of Cu(OH)2
∴ 200 g sodium hydroxide will from = `(98 xx 200)/80`
= 245 g of Cu(OH)2
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