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प्रश्न
What should be the angle of incidence for a ray of light which suffers a minimum deviation of 36° through an equilateral prism?
[Hint: A = 60°, i = (A + δmin)/2]
उत्तर
Given,
Angle of prism, A = 60°
Angle of minimum deviation, δmin = 36°
Angle of incidence, i = ?
As δmin = 2i - A
36° = 2i - 60°
i = 48°
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