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What should be the angle of incidence for a ray of light which suffers a minimum deviation of 36o through an equilateral prism? [Hint: A = 60°, i = (A + δmin)/2] - Physics

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Question

What should be the angle of incidence for a ray of light which suffers a minimum deviation of 36° through an equilateral prism?

[Hint: A = 60°, i = (A + δmin)/2]

Numerical

Solution

Given, 

Angle of prism, A = 60° 

Angle of minimum deviation, δmin  = 36°

Angle of incidence, i = ?

As  δmin  = 2i - A

36° = 2i - 60°

i = 48°

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Refraction of Light Through a Prism
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Chapter 4: Refraction of Light at Plane Surfaces - Exercise 4 (B) 3 [Page 88]

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Selina Physics [English] Class 10 ICSE
Chapter 4 Refraction of Light at Plane Surfaces
Exercise 4 (B) 3 | Q 2 | Page 88
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