Advertisements
Advertisements
प्रश्न
Which of the following hydrocarbons can decolourise bromine water and which cannot? Why?
C6H12, C6H14, C6H10
उत्तर
C6H12 (Hexene) and C6H10 (Hexyne or Cyclohexene ) are the hydrocarbons which can decolourize bromine water, as they are unsaturated. Bromine undergo addition reactions with unsaturated compounds like alkenes and alkynes containing a double or a triple bond. When bromine water is added to an unsaturated compound, the former gets added to the latter, thereby turning colourless from its reddish brown colour.
C6H14 (Hexane) is a hydrocarbon which cannot decolourize bromine water because it is a saturated compound (alkane). Saturated co
APPEARS IN
संबंधित प्रश्न
‘A’ is an element having four electrons in its outermost orbit. An allotropes ‘B’ of this element is used as a dry lubricant in machinery and in pencil leads. So:
i. Write the name of element ‘A’ and its allotropes.
ii. State whether ‘B’ is a good conductor or non-conductor of electricity?
Explain in brief two main reasons for carbon forming a large number of compounds.
Draw the electron dot structures for F2.
Which of the two is better for our health : butter or vegetable oil? Why?
Answer the following question.
Name a cyclic unsaturated carbon compound.
Pentane has the molecular formula C5 H12 It has
The name of the compound CH3 — CH2 — CHO is
Identify and name the functional groups present in the following compounds.
- \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{..}\\
\ce{H - C - C - C - OH}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{..}\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\
\end{array}\] - \[\begin{array}{cc}
\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{....}\\
\phantom{...}|\phantom{....}|\phantom{....}||\phantom{....}\\
\ce{H - C - C - C - OH}\\
\phantom{...}|\phantom{....}|\phantom{.........}\\
\phantom{}\ce{H}\phantom{...}\ce{H}\phantom{.......}\\
\end{array}\] - \[\begin{array}{cc}
\phantom{......}\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{O}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{.......}\\
\phantom{....}|\phantom{....}|\phantom{....}||\phantom{....}|\phantom{....}|\phantom{....}\\
\ce{H} - \ce{C} - \ce{C} - \ce{C} - \ce{C} - \ce{C} - \ce{H}\\
\phantom{....}|\phantom{.....}|\phantom{........}|\phantom{....}|\phantom{....}\\
\phantom{....}\ce{H}\phantom{....}\ce{H}\phantom{........}\ce{H}\phantom{..}\ce{H}\phantom{.....}\\
\end{array}\] - \[\begin{array}{cc}
\phantom{......}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{......}\\
\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}\\
\ce{H - C - C - C = C - H}\\
\phantom{....}|\phantom{....}|\phantom{.............}\\
\phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{.............}
\end{array}\]
What is the role of metal or reagents written on arrows in the given chemical reactions?
- \[\begin{array}{cc}
\ce{CH3}\phantom{.....}\ce{CH3}\phantom{.........}\ce{CH3}\phantom{..}\ce{CH3}\phantom{..........}\\
\phantom{...}\backslash\phantom{......}/\phantom{................}|\phantom{.....}|\phantom{............}\\
\ce{C} = \ce{C} + \ce{H2} \overset{\ce{Ni}}{\rightarrow} \ce{CH3 - C - C - CH3}\\
\phantom{.}/\phantom{........}\backslash\phantom{..............}|\phantom{....}|\phantom{.........}\\
\ce{CH3}\phantom{....}\ce{CH3}\phantom{............}\ce{H}\phantom{...}\ce{H}\phantom{........}
\end{array}\] - \[\ce{CH3COOH + CH3CH2OH \overset{\ce{Conc. H2SO4}}{\rightarrow}CH3COOC2H5 + H2O}\]
- \[\ce{CH3CH2OH}\ce{->[Alk.KMnO4][Heat]CH3COOH}\]
Write the name of the following compound
\[\begin{array}{cc}
\phantom{}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{.....}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{.....}\\
\ce{H} - \ce{C} - \ce{C} - \ce{C} ≡ \ce{C} - \ce{H}\\
\phantom{}|\phantom{....}|\phantom{..........}\\
\phantom{}\ce{H}\phantom{...}\ce{H}\phantom{..........}\\
\end{array}\]