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प्रश्न
Which isomer of C5H10 gives a single monochloro compound C5H9Cl in bright sunlight?
उत्तर
The molecular formula C5H10 can have a number of structural isomers.
However, the fact that the given compound produces a single monochloro derivative when reacted with Cl2 in sunlight implies that all of the H-atoms in the compound are equivalent. This is possible only if the compound is a cyclic alkane. Hence, the hydrocarbon is cyclopentane.
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संबंधित प्रश्न
The complex ion `[Co(H_2O)_5 (ONO)]^(2+) `
(A) linkage isomer
(B) ionisation isomer
(C) co-ordination isomer
(D) geometrical isomer
Give evidence that [Co(NH3)5Cl]SO4 and [Co(NH3)5SO4]Cl are ionization isomers.
What type of isomerism is shown by the complex [Co(NH3)5(SCN)]2+?
Write the IUPAC name of the complex [Cr(NH3)4Cl2]+. What type of isomerism does it exhibit?
Which of the following pair contains a complex salt and double salt respectively?
Which of the following complexes show linkage isomerism?
(i) \[\ce{[Co(NH3)5 (NO2)]^{2+}}\]
(ii) \[\ce{Co(H2O)5 CO]^{3+}}\]
(iii) \[\ce{[Cr(NH3)5 SCN]^{2+}}\]
(iv) \[\ce{Fe(en)2 Cl2]^+}\]
Match the complex species given in Column I with the possible isomerism given in Column II and assign the correct code:
Column I (Complex species) | Column II (Isomerism) |
A. \[\ce{[Co(NH3)4 Cl2]^+}\] | 1. optical |
B. \[\ce{cis-[Co(en)2 Cl2]^+}\] | 2. ionisation |
C. \[\ce{[Co(NH3)5 (NO2)]Cl2}\] | 3. coordination |
D. \[\ce{[Co(NH3)6][Cr(CN)6]}\] | 4. geometrical |
5. linkage |
Assertion: Linkage isomerism arises in coordination compounds containing ambidentate ligand.
Reason: Ambidentate ligand has two different donor atoms
A functional isomer of 1-butyne is
The complex [Co(NH3)5(NO2)]Cl2 is red in colour. Give IUPAC the name of its linkage isomer.