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Which of 0.1 M HCl and 0.1 M KCl do you expect to have greater mΛm∘ and why? - Chemistry

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प्रश्न

Which of 0.1 M HCl and 0.1 M KCl do you expect to have greater `Λ_"m"^∘` and why?

टीपा लिहा

उत्तर

Compare to 0.1 M HCl and 0.1 M KCl, 0.1 M HCl has greater molar conductance.

  1. Molar conductance of 0.1 M HCl = 39.132 × 10−3 S m2 mol−1
  2. Molar conductance of 0.1 M KCl = 12.896 × 10−3 S m2 mol−1
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Conductivity of Electrolytic Solution
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पाठ 9: Electro Chemistry - Evaluation [पृष्ठ ६६]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
पाठ 9 Electro Chemistry
Evaluation | Q 9. | पृष्ठ ६६

संबंधित प्रश्‍न

The number of electrons that have a total charge of 9650 coulombs is ____________.


The molar conductivity of a 0.5 mol dm−3 solution of AgNO3 with electrolytic conductivity of 5.76 × 10−3 S cm−1 at 298 K is ____________.


Electrolyte KCl KNO3 HCl NaOAC NaCl
Λ_
(S cm mol−1)
149.9 145.0 426.2 91.0 126.5

Calculate \[\ce{Λ^∘_{HOAC}}\] using appropriate molar conductances of the electrolytes listed above at infinite dilution in water at 25°C.


The equivalent conductance of `"M"/36` solution of a weak monobasic acid is 6 mho cm2 equivalent−1 and at infinite dilution is 400 mho cm2 equivalent−1. The dissociation constant of this acid is ____________.


A conductivity cell has been calibrated with a 0.01 M, 1 : 1 electrolytic solution (specific conductance (κ = 1.25 × 10−3 S cm−1) in the cell and the measured resistance was 800 Ω at 25°C. The cell constant is, ____________.


Conductivity of a saturated solution of a sparingly soluble salt AB (1 : 1 electrolyte) at 298 K is 1.85 × 10−5 S m−1. Solubility product of the salt AB at 298 K `(Λ_"m"^∘)_"AB"` = 14 × 10−3 S m2 mol−1.


Why does the conductivity of a solution decrease on dilution of the solution?


The conductivity of a 0.01 M solution of a 1 : 1 weak electrolyte at 298 K is 1.5 × 10−4 S cm−1.

i) molar conductivity of the solution

ii) degree of dissociation and the dissociation constant of the weak electrolyte

Given that

\[\ce{λ^∘_{cation}}\] = 248.2 S cm2 mol−1

\[\ce{λ^∘_{anion}}\] = 51.8 S cm2 mol−1


Arrange the following solutions in the decreasing order of specific conductance.

i) 0.01 M KCl

ii) 0.005 M KCl

iii) 0.1 M KCl

iv) 0.25 M KCl

v) 0.5 M KCl


Why is AC current used instead of DC in measuring the electrolytic conductance?


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