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प्रश्न
Which of the following sequence form an A.P.?
पर्याय
3, 6, 9, 15, ......
1, 8, 15, 22, 30, ....
2, 5, 9, 14, 20, ....
11, 22, 33, 44, 55, ....
उत्तर
11, 22, 33, 44, 55, ....
Explanation:
In the sequence: 11, 22, 33, 44, 55, .....
a2 – a1 = 22 – 11 = 11
a3 – a2 = 33 – 22 = 11
a4 – a3 = 44 – 33 = 11
a5 – a4 = 55 – 44 = 11
That is, the common difference is the same.
As a result, the sequence is an A.P
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संबंधित प्रश्न
If A = {11, 21, 31, 41}, B = {12, 22, 31, 32}, then find:
(1) A ∪ B
(2) A ∩ B
Find the first two terms of the following sequence:
tn = n +2 .
State whether the following sequence is an A.P. or not.
1,3,6,10,......
Choose the correct alternative answer for the following sub question.
What is the common difference of the sequence 0, – 4, – 8, – 12?
tn = 2n − 5 in a sequence, find its first two terms
Find first term of the sequence tn = 2n + 1
Find two terms of the sequence tn = 3n – 2
Decide whether the following sequence is an A.P. or not.
3, 5, 7, 9, 11 ........
Find first four terms of the sequence tn = n + 2
Kalpana saves some amount every month. In the first three months, she saves ₹ 100, ₹ 150, and ₹ 200 respectively. In how many months will she save ₹ 1200?
Activity :- Kalpana’s monthly saving is ₹ 100, ₹ 150, ₹ 200, ......, ₹ 1200
Here, d = 50. Therefore this sequence is an A.P.
a = 100, d = 50, tn = `square`, n = ?
tn = a + (n – 1) `square`
`square` = 100 + (n – 1) × 50
`square/50` = n – 1
n = `square`
Therefore, she saves ₹ 1200 in `square` months.
Find two consecutive positive even integers such that their product is 1520.
What will be the 6th, 12th and 25th term of the sequence defined by an = (n – 2)2 + 2n?
