Advertisements
Advertisements
प्रश्न
tn = 2n − 5 in a sequence, find its first two terms
उत्तर
tn = 2n − 5 .......[Given]
∴ t1 = 2(1) – 5
= 2 – 5
= – 3
t2 = 2(2) – 5
= 4 – 5
= – 1
∴ The first two terms of the sequence are – 3 and – 1.
APPEARS IN
संबंधित प्रश्न
If A = {11, 21, 31, 41}, B = {12, 22, 31, 32}, then find:
(1) A ∪ B
(2) A ∩ B
Find the first two terms of the following sequence:
tn = n +2 .
Choose the correct alternative answer for the following sub question.
What is the common difference of the sequence 0, – 4, – 8, – 12?
Find first term of the sequence tn = 2n + 1
Find two terms of the sequence tn = 3n – 2
Decide whether the following sequence is an A.P. or not.
3, 5, 7, 9, 11 ........
Find first four terms of the sequence tn = n + 2
Kalpana saves some amount every month. In the first three months, she saves ₹ 100, ₹ 150, and ₹ 200 respectively. In how many months will she save ₹ 1200?
Activity :- Kalpana’s monthly saving is ₹ 100, ₹ 150, ₹ 200, ......, ₹ 1200
Here, d = 50. Therefore this sequence is an A.P.
a = 100, d = 50, tn = `square`, n = ?
tn = a + (n – 1) `square`
`square` = 100 + (n – 1) × 50
`square/50` = n – 1
n = `square`
Therefore, she saves ₹ 1200 in `square` months.
Which of the following sequence form an A.P.?
Check whether 422 is in the sequence 10, 13, 16, 19, 22, ....
Find two consecutive positive even integers such that their product is 1520.
What will be the 6th, 12th and 25th term of the sequence defined by an = (n – 2)2 + 2n?
Find first term of the sequence tn = 3n − 2.
