मराठी

Which of the following species has tetrahedral geometry? - Chemistry

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प्रश्न

Which of the following species has tetrahedral geometry?

पर्याय

  • \[\ce{BH^{-}4}\]

  • \[\ce{NH^{-}2}\]

  • \[\ce{CO^{2-}3}\]

  • \[\ce{H3O+}\]

MCQ

उत्तर

\[\ce{BH^{-}4}\]

Explanation:

(i) The molecule of \[\ce{BH^{−}4}\] has four bond pairs and zero lone pair of electrons, so it will be a tetrahedral molecule.

(ii) \[\ce{NH^{-}2}\] has two bond pairs and two lone pairs of electrons on the nitrogen atom. So, it will have a bent geometry.

(iii) \[\ce{CO^{2-}3}\] has three bond pairs and no lone pairs of electrons on carbon atoms. So, it will have a trigonal planar geometry.

(iv) \[\ce{H3O+}\] has three bond pairs and one lone pair of electrons on oxygen atoms. So, it has a pyramidal geometry.

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पाठ 4: Chemical Bonding and Molecular Structure - Multiple Choice Questions (Type - I) [पृष्ठ ४०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 4 Chemical Bonding and Molecular Structure
Multiple Choice Questions (Type - I) | Q 7 | पृष्ठ ४०

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संबंधित प्रश्‍न

Explain the important aspects of resonance with reference to the `"CO"_3^(2-)` ion.


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Explain why \[\ce{CO^{2–}3}\] ion cannot be represented by a single Lewis structure. How can it be best represented?


Draw the resonating structure of ozone molecule


Draw the resonating structure of nitrate ion


Resonance structures can be written for ______.


The acceptable resonating structures of the following molecule are:

\[\begin{array}{cc}
\ce{CH3 - CH = C - \overset{\bullet\bullet}{\underset{\bullet\bullet}{O}} - CH2 - CH3}\\
|\phantom{......}\\
\ce{:N}\phantom{.......}\\
\phantom{}/\phantom{...}\backslash\phantom{......}\\
\phantom{}\ce{H3C}\phantom{.....}\ce{CH3}\phantom{......}
\end{array}\]

(x) \[\begin{array}{cc}
\ce{CH3 - \overset{\overset{Θ}{\bullet\bullet}}{C}H - C -  \overset{\bullet\bullet}{\underset{\bullet\bullet}{O}} - CH2 - CH3}\\
||\phantom{......}\\
\ce{N^⊕}\phantom{.....}\\
\phantom{}/\phantom{...}\backslash\phantom{......}\\
\phantom{}\ce{H3C}\phantom{.....}\ce{CH3}\phantom{......}
\end{array}\]
(y) \[\begin{array}{cc}
\ce{CH3 - \overset{\overset{Θ}{\bullet\bullet}}{C}H - C =  \overset{⊕}{\underset{\bullet\bullet}{O}} - CH2 - CH3}\\
|\phantom{......}\\
\ce{:N}\phantom{.......}\\
\phantom{}/\phantom{...}\backslash\phantom{......}\\
\phantom{}\ce{H3C}\phantom{.....}\ce{CH3}\phantom{......}
\end{array}\]
(z) \[\begin{array}{cc}
\ce{CH3 - \overset{⊕}{C}H - C -  \overset{\bullet\bullet}{\underset{\bullet\bullet}{O}} - CH2 - CH3}\\
||\phantom{......}\\
\ce{N^Θ}\phantom{.....}\\
\phantom{}/\phantom{...}\backslash\phantom{......}\\
\phantom{}\ce{H3C}\phantom{.....}\ce{CH3}\phantom{......}
\end{array}\]
(w) \[\begin{array}{cc}
\ce{CH3 - \overset{⊕}{C}H - C =  \overset{Θ}{O} - CH2 - CH3}\\
|\phantom{......}\\
\ce{:N}\phantom{.......}\\
\phantom{}/\phantom{...}\backslash\phantom{......}\\
\phantom{}\ce{H3C}\phantom{.....}\ce{CH3}\phantom{......}
\end{array}\]

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