Question

Which of the following will produce a buffer solution when mixed in equal volumes?

पर्याय

• 0.1 mol dm^–3 $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ and 0.1 mol dm^–3 $$\mathrm{HCl}$$

• 0.05 mol dm^–3 $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ and 0.1 mol dm^–3 $$\mathrm{HCl}$$

• 0.1 mol dm^–3 $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ and 0.05 mol dm^–3 $$\mathrm{HCl}$$

• 0.1 mol dm^–3 $$\mathrm{CH}{\phantom{A}}_4\mathrm{COONa}$$ and 0.1 mol dm^–3 $$\mathrm{NaOH}$$

Answer 1

0.1 mol dm^–3 $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ and 0.05 mol dm^–3 $$\mathrm{HCl}$$

Explanation:

When 0.1 mol dm^–3 $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ and 0.05 mol dm^–3 $$\mathrm{HCl}$$ react total amount of $$\mathrm{HCl}$$ reacts with $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ to form $$\mathrm{NH}{\phantom{A}}_4\mathrm{Cl}$$ and some $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ will be left unreacted. Thus, the resultant solution contains $$\mathrm{NH}{\phantom{A}}_4\mathrm{Cl}$$ and $$\mathrm{NH}{\phantom{A}}_4\mathrm{OH}$$ which will produce a buffer solution.