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प्रश्न
Without solving, comment upon the nature of roots of the following equation:
25x2 − 10x + 1 = 0
उत्तर
25x2 − 10x + 1 = 0
a = 25, b = −10 and c = 1
∴ Discriminant = b2 – 4ac
= (−10)2 − 4(25)(1)
= 100 – 100
= 0
Since D = 0, then equation has real and equal roots.
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