Question

Work done in converting one gram of ice at -10°C into steam at 100°C is ______.

पर्याय

• 3045 J

• 6056 J

• 721 J

• 616 J

Answer 1

Work done in converting one gram of ice at -10°C into steam at 100°C is 721 J.

Explanation:

ΔQ = `[1 xx 1/2 xx 10 + 1 xx 80 + 1 xx 1 xx 100 + 1 xx 536]`

= 721 cal