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Question
Work done in converting one gram of ice at -10°C into steam at 100°C is ______.
Options
3045 J
6056 J
721 J
616 J
MCQ
Fill in the Blanks
Solution
Work done in converting one gram of ice at -10°C into steam at 100°C is 721 J.
Explanation:
ΔQ = `[1 xx 1/2 xx 10 + 1 xx 80 + 1 xx 1 xx 100 + 1 xx 536]`
= 721 cal
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Calorimetry
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