Advertisements
Advertisements
प्रश्न
Write the quadratic equation whose roots are ‒2 and ‒3.
उत्तर
Let the roots be α = –2 and β = –3.
∴ α + β = (–2) + (–3) = –5 and αβ = (–2)(–3) = 6
Hence, the required quadratic equation is
x2 – (α + β)x + α β = 0
i.e. x2 – (–5)x + 6 = 0
i.e. x2 + 5x + 6 = 0
APPEARS IN
संबंधित प्रश्न
In the following, determine whether the given values are solutions of the given equation or not:
x2 + x + 1 = 0, x = 0, x = 1
An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore. If the average speed of the express train is 1 1 km/hr more than that of the passenger train, form the quadratic equation to find the average speed of express train.
Solve : x(x – 5) = 24
Solve the following equation for x and give, in the following case, your answer correct to 2 decimal places:
`4x + 6/x + 13 = 0`
An Aero plane travelled a distance of 400 km at an average speed of x km/hr. On the return journey, the speed was increased by 40 km/hr. Write down an expression for the time taken for:
(1) the onward journey;
(2) the return journey.
If the return journey took 30 minutes less than the onward journey, write down an equation in x and find its value.
Find the quadratic equation, whose solution set is:
{−2, 3}
Solve the following equation using the formula:
`(x - 1)/(x - 2) + (x - 3)/(x - 4) = 3 1/3`
`3sqrt(x/5)+3sqrt(5/x)=10`
`sqrt3x^2+11x+6sqrt3=0`
`1/x-1-1/(x+5)=6/7,x≠1,-5`
`3((3x-1)/(2x+3))-2((2x+3)/(3x-1))=5,x≠1/3,-3/2`
A plane left 40 minutes late due to bad weather and in order to reach its destination, 1600kms away in time, it had to incease its speed by 400km/ hr from its usual speed. Find the usual speed of the plane.
An aeroplane takes 1 hour less for a journey of 1200km, if its speed is increased by 100km/ hrfrom its usual speed. Find the usual speed.
A scholarship account of Rs 75,000 was distributed equally among a certain number of students. Had there been 10 students more, each would have got Rs 250 less. Find the original number of persons.
Find the value of k for which the equation 3x2 – 6x + k = 0 has distinct and real roots.
Solve : x4 - 10x2 +9 =0
Solve:
`3sqrt(2x^2) - 5x - sqrt2 = 0`
Solve `9("x"^2 + 1/"x"^2) -3("x" - 1/"x") - 20 = 0`
Solve the following equation by using formula :
`x(3x + 1/2)` = 6