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प्रश्न
`sqrt3x^2+11x+6sqrt3=0`
उत्तर
Given:
`sqrt3x^2+11x+6sqrt3=0`
⇒`sqrt3x^2+9x+2x+6sqrt3=0`
⇒`sqrt3x(x+3sqrt3)+2(x+3sqrt3)=0`
⇒`(x+3sqrt3)(sqrt3x+2)=0`
⇒`x+3sqrt3= or sqrt3x+2=0`
⇒`x=-3sqrt3 or x=(-2)/sqrt3=(-2xxsqrt3)/(sqrt3xxsqrt3)=(-2sqrt3)/3`
Hence, the roots of the equation are `-3sqrt3` and `(-2sqrt3)/3`
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