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प्रश्न
`3sqrt7x^2+4x-sqrt7=0`
उत्तर
Given:
`3sqrt7x^2+4x-sqrt7=0`
⇒`3sqrt7x^2+7x-3x-sqrt7=0`
⇒`sqrt7x(3x+sqrt7)-1(3x+sqrt7)=0`
⇒`(3x+sqrt7) (sqrt7-1)=0`
⇒`3x+sqrt7`=0 or `sqrt7x-1=0`
⇒`x=-sqrt7/3` or `x=1/sqrt7=(1xxsqrt7)/(sqrt7xxsqrt7)=sqrt7/7`
Hence, the roots of the equation are `-sqrt7/3` and `sqrt7/7`
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