Advertisements
Advertisements
प्रश्न
`sqrt7x^2-6x-13sqrt7=0`
उत्तर
We write,
`-66x=7x-13x ` as `sqrt7x^2xx(-13sqrt7)=91x^2=7x xx(-13x)`
∴`sqrt7x^2-6x-13sqrt7=0`
⇒`sqrt7x^2+7x-13x-13sqrt7=0`
⇒`sqrt7x(x+sqrt7)-13(x+sqrt7)=0`
⇒`(x+sqrt7)(sqrt7x-13)=0`
⇒`x+sqrt7=0` or `sqrt 7x-13=0`
⇒`x=-sqrt7 or x=13/sqrt7=(13sqrt7)/7`
Hence, the roots of the given equation are`-sqrt7` and `13/sqrt7/7`
APPEARS IN
संबंधित प्रश्न
If α + β = 5 and α3 +β3 = 35, find the quadratic equation whose roots are α and β.
Solve the following equation for x and give, in the following case, your answer correct to 2 decimal places:
x2 – 5x – 10 = 0
Without solving, comment upon the nature of roots of the following equation:
`x^2 + 2sqrt(3)x - 9 = 0`
`x/(x+1)+(x+1)/x=2 4/15, x≠ 0,1`
A scholarship account of Rs 75,000 was distributed equally among a certain number of students. Had there been 10 students more, each would have got Rs 250 less. Find the original number of persons.
Find which of the following equations are quadratic:
7x3 – 2x2 + 10 = (2x – 5)2
Find the value of k for which the equation 3x2 – 6x + k = 0 has distinct and real roots.
Solve:
`((3x + 1)/(x + 1)) + ((x + 1)/(3x + 1)) = 5/2`
Solve:
`2((2x - 1)/(x + 3)) - 3((x + 3)/(2x - 1)) = 5; x ≠ -3, (1)/(2)`
Solve:
`9(x^2 + 1/x^2) - 9(x + 1/x) - 52 = 0`
