Question

Write the reaction when ethylamine is treated with Hinsberg's reagent.

Answer 1

When ethylamine (C₂H₅NH₂) reacts with Hinsberg's reagent, it forms N-ethylbenzenesulfonamide, which is soluble in alkali (NaOH).

$$\mathrm{C}{\phantom{A}}_2\mathrm{H}{\phantom{A}}_5\mathrm{NH}{\phantom{A}}_2+\mathrm{C}{\phantom{A}}_6\mathrm{H}{\phantom{A}}_5\mathrm{SO}{\phantom{A}}_2\mathrm{Cl}⟶\mathrm{C}{\phantom{A}}_6\mathrm{H}{\phantom{A}}_5\mathrm{SO}{\phantom{A}}_2\mathrm{NHC}{\phantom{A}}_2\mathrm{H}{\phantom{A}}_5+\mathrm{HCl}$$