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प्रश्न
Write two solutions of the form x = 0, y = a and x = b, y = 0 for the following equation :
−4x + 3y = 12
उत्तर
Given that ,
−4x + 3y = 12
Substituting x = 0 in the equation
−4x + 3y = 12 , we get
⇒ - 4 × 0 + 3 y = 12
⇒ 3y = 12
⇒ y = 4
Thus x = 0 and y = 4 is a solution of −4x + 3y = 12
Substituting y = 0 in the equation
−4x + 3y = 12 , we get
⇒ - 4x + 3 × 0 = 12
⇒ -4x = 12
⇒ `x = 12 / -4 = -3`
Thus, x = -3 and y = 0 is a solution of −4x + 3y = 12 .
Thus x = 0. y = 4 and x = -3. y = 0 are two solutions of −4x + 3y = 12
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