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Write Two Uses of Pulleys. is Pulley a Force Multiplier? - Physics

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प्रश्न

Write two uses of pulleys. Is pulley a force multiplier?

एका वाक्यात उत्तर

उत्तर

Two uses of pulley:
(i) To change the direction of application of force to a convenient direction.
(ii) To multiply force.
Yes, a pulley is a force multiplier

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Force, Work, Energy and Power - Exercise 1.3 ii [पृष्ठ २९]

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फ्रँक Physics - Part 2 [English] Class 10 ICSE
पाठ 1 Force, Work, Energy and Power
Exercise 1.3 ii | Q 2 | पृष्ठ २९

संबंधित प्रश्‍न

Answer the following in detail.

How does a pulley make work simpler? 


Solve the following numerical problem.

What effort will be required to lift a load of 500 N by a single movable pulley? [Hint: Mechanical advantage of a single movable pulley is two].


What is a gear system ?


Give reason for the following:

In case of a block and tackle arrangement, the mechanical advantage increases with the increase in the number of pulleys.


A pulley system has a velocity ratio 3. Draw a diagram showing the point of application and direction of load (L), effort (E) and tension (T). It lifts a load of 150 N by an effort of 60 N. Calculate its mechanical advantage. Is the pulley system ideal? Give reason.


Name the type of single pulley that can act as a force multiplier. Draw a labeled diagram of the pulley mentioned by you.


What is a block and tackle system of pulleys?


What is the relation between the mechanical advantage and the number of strands of string used to support the load, in a ‘block and tackle’ set-up?


A pulley system has a velocity ratio of 4 and an efficiency of 90%. Calculate:
(i) the mechanical advantage of the system.
(ii) the effort required to raise a load of 300 N by the system.


A block and tackle system of pulleys has velocity ratio 4.

  1. Draw a labelled diagram of the system indicating clearly, the direction of the load and effort.
  2.  Calculate the potential energy of the load 100 kgf lifted by this pulley to a height 5 m. (g = 10 ms-2)

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