Question

`lim_("x" -> pi/2)` [sinx] is equal to ____________.

पर्याय

• 1

• -1

• None of these

• 0

Answer 1

`lim_("x" -> pi/2)` [sinx] is equal to 0.

Explanation:

`lim_("x" -> pi/2) ["sin x"] = 0 ["since" pi/2 - "h" le "x" le pi/2 + "h"]`