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Question
`lim_("x" -> pi/2)` [sinx] is equal to ____________.
Options
1
-1
None of these
0
MCQ
Fill in the Blanks
Solution
`lim_("x" -> pi/2)` [sinx] is equal to 0.
Explanation:
`lim_("x" -> pi/2) ["sin x"] = 0 ["since" pi/2 - "h" le "x" le pi/2 + "h"]`
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