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Question
`(1 - 2[cos 60^circ - cos 80^circ])/(2 sin 10^circ)` = ______.
Options
2
1
`1/2`
`3/2`
MCQ
Fill in the Blanks
Solution
`(1 - 2[cos 60^circ - cos 80^circ])/(2 sin 10^circ)` = 1.
Explanation:
We have, `(1 - 2[cos 60^circ - cos 80^circ])/(2 sin 10^circ)`
`= (1 - 2(1/2 - cos 80^circ))/(2 sin 10^circ)`
`= (2 cos 80^circ)/(2 sin 10^circ)`
`= (cos (90^circ - 10^circ))/(sin 10^circ)`
`= (sin 10^circ)/(sin 10^circ)` = 1
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Trigonometric Functions of Allied Angels
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