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100 cells each of emf 5 V and internal resistance 1 Ω are to be arranged so as to produce maximum current in a 25 Ω resistance. Each row contains equal number of cells. The number of rows should be - Physics

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Question

100 cells each of emf 5 V and internal resistance 1 Ω are to be arranged so as to produce maximum current in a 25 Ω resistance. Each row contains equal number of cells. The number of rows should be ______.

Options

  • 2

  • 4

  • 5

  • 100

MCQ
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Solution

100 cells each of emf 5 V and internal resistance 1 Ω are to be arranged so as to produce maximum current in a 25 Ω resistance. Each row contains equal number of cells. The number of rows should be 2.

Explanation:

let, m = Number of rows

n = Number of cells in a row

∴ m × n = 100    ....(i)

Resistance in series = nr

Resistance in parallel = `("nr")/"m"`

For maximum current, R = `("nr")/"m"`

25 = `"n"/"m"`   ........(r = 1 Ω)     ....(ii)

From equations (i) and (ii),

m = 2

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Chapter 11: Electric Current Through Conductors - Exercises [Page 219]

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Balbharati Physics [English] 11 Standard Maharashtra State Board
Chapter 11 Electric Current Through Conductors
Exercises | Q 1. (vii) | Page 219

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