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Question
`2/x^2-5/x+2=0`
Solution
`2/x^2-5/x+2=0`
⇒`2-5x+2x^2=0` [Multiplying both sides by `x^2` ]
⇒`2x^-5x+2=0`
⇒`2x^2-(4x+x)+2=0`
⇒`2x^2-4x-x+2=0`
⇒`2x(x-2)-1(x-2)=0`
⇒`(2x-1) (x-2)=0`
⇒`2x=1=0 or x-2=0`
⇒ `x=1/2 or x=2`
Hence, the roots of the equation are `1/2` and 2.
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