Advertisements
Advertisements
Question
`2x^2+ax-a^2=0`
Solution
We write, `ax=2ax-ax as 2x^2xx(-a^2)=-2a^2x^2=2axx(-ax)`
∴` 2x^2+ax-a^2=0`
`⇒2x^2+2ax-ax-a^2=0`
`⇒2x(x+a)-a(x+a)=0`
`⇒(x+a)(2x-a)=0`
`⇒x+a=0 or 2x-a=0`
`⇒x=-a or x=a/2`
Hence, -a and ` a/2`are the roots of the given equation.
APPEARS IN
RELATED QUESTIONS
Represent the following situation in the form of a quadratic equation:
Rohan's mother is 26 years older than him. The product of their ages (in years) 3 years from now will be 360. We would like to find Rohan's present age.
Solve x2 + 7x = 7 and give your answer correct to two decimal places
Solve : x(x – 5) = 24
Solve `x/a - (a + b)/x = (b(a +b))/(ax)`
Solve the following equation and give your answer correct to 3 significant figures: 5x² – 3x – 4 = 0
Without solving, comment upon the nature of roots of the following equation:
`x^2 + 2sqrt(3)x - 9 = 0`
`3sqrt(x/5)+3sqrt(5/x)=10`
`9x-3x-2=0`
Solve the following equation by using formula :
x2 + 7x – 7 = 0
Solve the following equation by using formula :
`(1)/x + (1)/(x - 2) = 3, x ≠ 0, 2`
