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प्रश्न
`2x^2+ax-a^2=0`
उत्तर
We write, `ax=2ax-ax as 2x^2xx(-a^2)=-2a^2x^2=2axx(-ax)`
∴` 2x^2+ax-a^2=0`
`⇒2x^2+2ax-ax-a^2=0`
`⇒2x(x+a)-a(x+a)=0`
`⇒(x+a)(2x-a)=0`
`⇒x+a=0 or 2x-a=0`
`⇒x=-a or x=a/2`
Hence, -a and ` a/2`are the roots of the given equation.
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