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प्रश्न
In the following, find the value of k for which the given value is a solution of the given equation:
7x2 + kx - 3 = 0, `x=2/3`
उत्तर
e are given here that,
7x2 + kx - 3 = 0, `x=2/3`
Now, as we know that `x=2/3` is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting `x=2/3` in the above equation gives us,
7x2 + kx - 3 = 0
`7(2/3)^2+k(2/3)-3=0`
`7(4/9)+(2k)/3-3=0`
`28/9+(2k/3)-3=0`
`(2k)/3=3-28/9`
`(2k)/3=(27-28)/9`
`(2k)/3=(-1)/9`
`2k=(-1)/9xx3`
`2k=(-3)/9`
`k=((-3)/9)/2`
`k=(-3)/(9xx2)`
`k=(-3)/18`
`k=(-1)/6`
Hence, the value of `k=(-1)/6`
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