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3 boys and 3 girls are to sit in a row. How many ways can this be done if boys and girls are at alternate places - Mathematics and Statistics

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Question

3 boys and 3 girls are to sit in a row. How many ways can this be done if boys and girls are at alternate places

Sum

Solution

Since boys and girls are at alternate places, the 3 boys can occupy 3 odd places (Ist, 3rd, Sth) in 3P3 ways and 3 girls can occupy 3 even places (2nd, 4th, 6th) in 3P3, ways or the 3 boys can occupy 3 even places in 3P3, ways and 3 girls can occupy 3 odd places in 3P3, ways.

Hence, the total number of seating arrangements in which boys and girls are at alternate places.

= 3P3 ×  3P33P3 ×  3P3

= 3!3! + 3!3!

= 2 (3!)2

= 2(3 × 2 ×1)2

= 2 × 36

= 72

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Permutations - Permutations When Repetitions Are Allowed
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Chapter 3: Permutations and Combination - Exercise 3.3 [Page 55]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
Chapter 3 Permutations and Combination
Exercise 3.3 | Q 17. (iii) | Page 55

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