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Question
`3x^2-243=0`
Solution
Given:
`3x^2-243=0`
`⇒3(x^2-81)=0`
`⇒ (x)^2-(9)^2=0 `
`⇒ (x+9)(x-9)=0`
`⇒ x+9=0 or x-9=0`
⇒ x=-9 or x=9
Hence, -9 and 9 are the roots of the equation `3x^2-243=0`
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