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Question
40 g of ice at -16°C is dropped into water at 0°C, when 4 g of water freezes into ice. If specific heat capacity of ice is 2100 J/kg°C, what will be the latent heat of fusion of ice?
Solution
Let the latent heat of fusion of ice be L.
Heat gained by ice at -16°C to convert to 0°C = Heat given out by 4 g of water to at 0°C to freeze into ice at 0°C
(40 x 2.1 x -16) = 4 x L
1344 = 4 L
L = 336 J/g
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