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Question
400 g of water at 80°C is mixed with 1 kg of water at 20°C. If the sp. heat cap. of water is 4200 J/kgK, find the final temperature of the mixture.
Numerical
Solution
Let the final temperature of the mixture be 8°C.
Heat lost by hot water = Heat gained by oold water
0.4 x C x (80 - θ) = 1 x C x (θ - 20)
or, 32 - 0.48 = θ - 20
or, θ = 37.14°C
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