Advertisements
Advertisements
Question
A burner raises the temperature of 360 g of water from 40°C to 100°C in 5 minutes. Calculate the rate of heat supplied by the burner.
Solution
m = 360 g = O .36 kg
Change in temperature, ΔT = (100 - 40)°C = 60°C = 60 K
Amount of heat required, Q = m x C x ΔT
= 0.36 x 4200 x 60 = 90720 J
Time taken = 5 min = 300 sec
Rate of heat supplied = `"Q"/"t" = 90720/300` = 302.4 J/s
APPEARS IN
RELATED QUESTIONS
An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0℃ to 15.0℃ in100 s. Calculate:
- the heat capacity of 4.0 kg of liquid,
- the specific heat capacity of the liquid.
It is generally cold after a hail-storm then during and before the hail storm. Give reason.
How will rise in sea level affect population in coastal countries?
How will global warming disturb the ecological balance?
What is carbon tax?
Water boils at 120 °C in a pressure cooker. Explain the reason
A certain amount of heat Q will warm 1 g of material X by 3°C and 1 g of material Y by 4°C. Which material has a higher specific heat capacity?
A piece of iron of mass 2.0 kg has a thermal capacity of 966 J/°C. What is its specific heat capacity in S.I. units?
Derive Mayer’s relation.
The cold object the hot object enclosed in one box of heat-resistant material.
- What changes will occur in the two objects when temperature flows from those objects?
- Which principle can show that the energy exchange takes place between two objects only when kept in isolated system?
