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Question
`(42"a"^4"b"^5(_))/(6"a"^4"b"^2)` = `(_)"b"^((_))"c"^2`
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Solution
`(42"a"^4"b"^5("c"^2))/(6"a"^4"b"^2)` = (7)b3c2
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Chapter 3: Algebra - Exercise 3.2 [Page 85]
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