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Question
5% pupil in a town died due to some diseases and 3% of the remaining left the town. If 2, 76, 450 pupil are still in the town; find the original number of pupil in the town.
Solution
Let original number of pupil in the town = 100
Number of pupil died due to disease
= `(5)/(100) xx 100` = 5
Remaining pupil = 100 - 5 = 95
Number of pupil who left the town
= `(3)/(100) xx 95`
= `(3 xx 95)/(100)`
= `(57)/(20)`
Actual remaining pupil
= `95 - (57)/(20)`
= `(1900 - 57)/(20)`
= `(1843)/(20)`
If the remaining pupil in the town are `(1843)/(20)`, then original number of pupil = 100
If the remaining pupil in the town is 1, then original number of pupil = `100 xx (20)/(1843)`
If the remaining pupil in the town are 276450, the original number of pupil
= `100 xx (20)/(1843)xx 276450`
= `(100 xx 20 xx 276450)/(1843)`
= 100 × 20 × 150
= 3,00,000.
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| Assessment Report for 2009-2010 | |||||
| Class : 9B | Name : Vidit Atrey | Date : 31 March 2010 | |||
| Subject | Internal assessment |
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