Advertisements
Advertisements
Question
`5x^2-4x+1=0`
Solution
The given equation is
`5x(x-2)+6=0`
⇒`5x^2-10x+6=0`
This is of the form `ax^2+bx+c=0` where `a=5, b=-10 and c=6`
∴ Discriminant` D=b^2-4ac=(-10)^2-4xx5xx6=100-120=-20<0`
Hence, the given equation has no real roots.
APPEARS IN
RELATED QUESTIONS
Write the discriminant of the following quadratic equations:
x2 + 2x + 4 = 0
Write the discriminant of the following quadratic equations:
x2 - 2x + k = 0, k ∈ R
Write the discriminant of the following quadratic equations:
x2 - x + 1 = 0
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
3x2 - 2x + 2 = 0
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
x2 - 2x + 1 = 0
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
`2x^2+5sqrt3x+6=0`
` 2x^2-7x+6=0`
`1/x-1/(x-2)=3,x≠0,2`
For what values of p are the roots of the equation `4x^2+px+3=0` real and equal?
If -4 is a root of the equation `x^2+2x+4p=0` find the value of k for the which the quadratic equation ` x^2+px(1+3k)+7(3+2k)=0` has equal roots.
