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Question
Find the nature of roots of the following quadratic equations:
`5x^2-4x+1=0`
Solution
The given equation is `5x^2-4x+1=0`
This is of the form `ax^2+bx+c=0` where `a=3,b=-2sqrt6 and c=2`
∴ Discriminant, `D=b^2-4ac=(-2sqrt6)^2-4xx3xx2=24-24=0`
Hence, the given equation has real and equal roots.
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