Question

${\displaystyle 9x^2+6x+1=0}$

Answer 1

${\displaystyle 9x^2+6x+1=0}$ 

${\displaystyle \Rightarrow 9x^2+3x+3x+1=0}$ 

${\displaystyle \Rightarrow 3x(3x+1)+1(3x+1)=0}$ 

${\displaystyle \Rightarrow (3x+1)(3x+1)=0}$ 

${\displaystyle \Rightarrow 3x+1=0 \text{or} 3x+1=0}$ 

${\displaystyle \Rightarrow x=\frac{-1}{3} \text{or} x\frac{-1}{3}}$ 

Hence, ${\displaystyle \frac{-1}{3}}$is the root of the equation ${\displaystyle 9x^2+6x+1=0}$