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प्रश्न
`9x^2+6x+1=0`
उत्तर
`9x^2+6x+1=0`
`⇒ 9x^2+3x+3x+1=0`
`⇒3x(3x+1)+1(3x+1)=0`
`⇒(3x+1) (3x+1)=0`
`⇒ 3x+1=0 or 3x+1=0`
`⇒ x=(-1)/3 or x(-1)/3`
Hence, `(-1)/3`is the root of the equation `9x^2+6x+1=0`
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