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Question
A and B are two events such that, P(A) = 0.42, P(B) = 0.48, and P(A ∩ B) = 0.16. Find P(A or B)
Solution
P(A) = 0.42
P(B) = 0.48
P(A ∩ B) = 0.16
P(A or B) = P(A ∪ B)
= P(A) + P(B) – P(A ∩ B)
= 0.42 + 0.48 – 0.16
= 0.74
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