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Question
A and B are two events such that, P(A) = 0.42, P(B) = 0.48, and P(A ∩ B) = 0.16. Find P(not A)
Solution
P(A) = 0.42
P(B) = 0.48
P(A ∩ B) = 0.16
P(not A) = `"P"(bar"A")`
= 1 – P(A)
= 1 – 0.42
=
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