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Question
A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A ∩ B) = 0.35.
Find
- P(A ∪ B)
- P(A′ ∩ B′)
- P(A ∩ B′)
- P(B ∩ A′)
Sum
Solution
- P(A) = 0.54, P(B) = 0.69, P(A ∩ B) = 0.35
P(A ∪ B) = P(A) + P(B) – (A ∩ B)
= 0.54 + 0.69 – 0.35
= 0.88 - P(A’ ∩ B’) = P[(A ∪ B)’] = 1 – P(A ∪ B)
1 – 0.88
= 0.12 - P(A ∩ B’) = P(A) – P(A ∩ B)
0.54 – 0.35
= 0.19 - P(B ∩ A’) = P(B) – P(B ∩ A)
= 0.69 – 0.35
= 0.34
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