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Question
A bag contains 19 tickets, numbered from 1 to 19. Two tickets are drawn randomly in succession with replacement. Find the probability that both the tickets drawn are even numbers.
Solution
Total numbers of tickets n(S) = 19
Even numbers E = {2, 4, 6, 8, 10, 12, 14, 16, 18}
n(E) = 9
Probability of getting even number on first ticket
= `(n(E))/(n(S))`
= `9/19`
∵ Replacement of ticket is allowed.
So probability of getting even number of second ticket drawn = `9/19`
Hence required probability = `9/19 xx 9/19 = 81/361`
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