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Question
A bag contains 3 red, 3 white, 3 green, and 3 black balls. One ball is picked up from the bag at random. What is the probability that the ball drawn is:
a. white
b. not white.
Solution
Let three red balls are R1 ,R2 ,R3
Three White balls are W1, W2, W3
Three green balls G1, G2,G3
Three black balls B1, B2, B3
S = {R1 ,R2 ,R3 , W1, W2, W3 , G1, G2,G3 , B1, B2, B3}
n(S) = 12
(a) Let A be the set of white balls
A = {W1, W2, W3}
n(A) = 3
P(A) = `("n"("A"))/("n"("S")) = 3/12 = 1/4`
(b) Let B be the set of not white balls.
B = {R1 ,R2 ,R3 ,G1, G2,G3 , B1, B2, B3}
n(B) = 9
P(A) =`("n"("B"))/("n"("S")) = 9/12 = 3/4`
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