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Question
A bag contains 5 red balls, 6 white balls, 7 green balls, 8 black balls. One ball is drawn at random from the bag. Find the probability that the ball drawn is black or red
Solution
Sample space (S) = 5 + 6 + 7 + 8
n(S) = 26
Let A be the event of getting a black ball
n(A) = 8
P(A) = `("n"("A"))/("n"("S")) = 8/26`
Let B be the event of getting a red ball
n(B) = 5
P(B) = `("n"("B"))/("n"("S")) = 5/26`
Probability of getting black or red ball
P(A ∪ B) = P(A) + P(B)
= `8/26 + 5/26`
= `13/26`
= `1/2`
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