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Question
A ball is thrown vertically upward from the ground with an initial velocity of 39.2 m/sec. If the only force considered is that attributed to the acceleration due to gravity, find the speed with which will it strike the ground?
Solution
Initial velocity of the ball = 39.2 m/s
Let s be the distance of the ball from the ground at time t.
u = 39.2m/s.
s = `"ut" - 1/2 * "gt"^2` where g = 9.8 m/sec.
s = `39.2"t" - 1/2 xx (9.8)"t"^2`
s = 39.2t – 49t2
At t = 8
(1) ⇒ v = – 9.8(8) + 39.2
= – 78.4 + 39.2
= – 39.2
∴ The speed with which the ball will strike the ground is = 39.2 m/s
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