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Question
If f'(x) = 4x – 5 and f(2) = 1, find f(x)
Solution
`int f"'"(x)"d"x = int(4x - 5)"d"x`
f(x) = `(4x^2)/2 - 5x + "c"`
f(x) = 2x2 – 5x + c
But f(2) = 1
2(2)2 – 5(2) + c = 1
8 – 10 + c = 1
c = 3
Thus, f(x) = 2x2 – 5x + 3
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