Advertisements
Advertisements
Question
A body starts from rest with uniform acceleration 2 m s-2. Find the distance covered by the body in 2 s.
Solution
Initial velocity u = 0
Acceleration a = 2 m/s2
Time t = 2 s
Let 'S' be the distance covered.
Using the second equation of motion,
S = ut + (1/2) at2
S = 0 + (1/2) (2) (2) 2
S = 4 m
APPEARS IN
RELATED QUESTIONS
Clarify the difference.
Distance and displacement
Differentiate between distance and displacement.
What can you say about the nature of motion of a body if its displacement-time graph is A straight line inclined to the time axis with an acute angle?
How is the distance related with time for motion under uniform acceleration such as the motion of a freely falling body?
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Compare the distance travelled in part BC with the distance travelled in part AB.
A body starts with an initial velocity of 10m s-1 and acceleration 5 m s-2. Find the distance covered by it in 5 s.
Explain the following concept in your own words with everyday examples:
Distance
Which of the following figures represent uniform motion of a moving object correctly?
______ is the length of the actual path covered by a body.
Assertion: If the displacement of the body is zero, the distance covered by it may not be zero.
Reason: Displacement is a vector & distance is a scalar quantity.
